Difference between revisions of "Sum of totient equals zeta(z-1)/zeta(z) for Re(z) greater than 2"

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==References==
 
==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=findme|next=Sum of totient equals z/((1-z) squared)}}: $24.3.2 I.B.$
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Euler totient|next=Sum of totient equals z/((1-z) squared)}}: $24.3.2 I.B.$
  
 
[[Category:Theorem]]
 
[[Category:Theorem]]
 
[[Category:Unproven]]
 
[[Category:Unproven]]

Revision as of 04:48, 22 June 2016

Theorem

The following formula holds for $\mathrm{Re}(z) > 2$: $$\displaystyle\sum_{k=1}^{\infty} \dfrac{\phi(k)}{k^z} = \dfrac{\zeta(z-1)}{\zeta(z)},$$ where $\phi$ denotes the totient and $\zeta$ denotes the Riemann zeta function.

Proof

References