View source for T(n)^2=T(T(n))+T(T(n)-1)

==Theorem==
The following formula holds for $n=2,3,4,\ldots$:
$$T(n)^2=T(T(n))+T(T(n)-1),$$
where $T(n)$ denotes the $n$th [[triangular numbers|triangular number]].

==Proof==

==References==
* {{PaperReference|Triangular numbers|1974|V.E. Hoggatt, Jr|author2=Marjorie Bicknell|prev=N^2=T(n)+T(n-1)|next=T(n+1)^2-T(n)^2=(n+1)^3}} $(1.4)$

[[Category:Theorem]]
[[Category:Unproven]]