Difference between revisions of "Taylor series of log(1-z)"
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Revision as of 23:41, 3 June 2016
Theorem
The following formula holds: $$\log(1-z)=-\displaystyle\sum_{k=1}^{\infty} \dfrac{z^k}{k},$$ where $\log$ denotes the logarithm.
Proof
References
1926: Leonard Lewin: Polylogarithms and Associated Functions (2nd ed.) ... (previous): (1.2)
