Taylor series of log(1-z)
From specialfunctionswiki
Theorem
The following formula holds: $$\log(1-z)=-\displaystyle\sum_{k=1}^{\infty} \dfrac{z^k}{k},$$ where $\log$ denotes the logarithm.
Proof
References
- 1958: Leonard Lewin: Dilogarithms and Associated Functions ... (previous) ... (next): $(1.2)$
- 1981: Leonard Lewin: Polylogarithms and Associated Functions (2nd ed.) ... (previous) ... (next): $(1.2)$
