Difference between revisions of "Weierstrass factorization of cosh"

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==Theorem==
<strong>[[Weierstrass factorization of cosh|Theorem]]:</strong> The [[Weierstrass factorization]] of [[cosh|$\cosh(x)$]] is
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The [[Weierstrass factorization]] of [[cosh|$\cosh(x)$]] is
 
$$\cosh x = \displaystyle\prod_{k=1}^{\infty} 1 + \dfrac{4x^2}{(2k-1)^2\pi^2}.$$
 
$$\cosh x = \displaystyle\prod_{k=1}^{\infty} 1 + \dfrac{4x^2}{(2k-1)^2\pi^2}.$$
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<strong>Proof:</strong>  █
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==Proof==
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==References==
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 00:00, 17 June 2016

Theorem

The Weierstrass factorization of $\cosh(x)$ is $$\cosh x = \displaystyle\prod_{k=1}^{\infty} 1 + \dfrac{4x^2}{(2k-1)^2\pi^2}.$$

Proof

References