View source for Z/(1-sqrt(q))2Phi1(q,sqrt(q);sqrt(q^3);z)=Sum z^k/(1-q^(k-1/2))

==Theorem==
The following formula holds:
$$\dfrac{z}{1-\sqrt{q}} {}_2\phi_1 \left(q,\sqrt{q};\sqrt{q^3};z \right) = \displaystyle\sum_{k=1}^{\infty} \dfrac{z^k}{1-q^{k-\frac{1}{2}}},$$
where ${}_2\phi_1$ denotes [[basic hypergeometric phi]].

==Proof==

==References==
* {{BookReference|Higher Transcendental Functions Volume I|1953|Arthur Erdélyi|author2=Wilhelm Magnus|author3=Fritz Oberhettinger|author4=Francesco G. Tricomi|prev=2Phi1(q,-1;-q;z)=1+2Sum z^k/(1+q^k)|next=findme}}: $4.8 (8)$

[[Category:Theorem]]
[[Category:Unproven]]