Log 10(z)=log(z)/log(10)
From specialfunctionswiki
Theorem
The following formula holds: $$\log_{10}(z)=\dfrac{\log(z)}{\log(10)},$$ where $\log_{10}$ denote logarithm base a and $\log$ denotes logarithm.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $4.1.22$