Series for log(z) for absolute value of (z-1) less than 1

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Theorem

The following formula holds for $|z-1| \leq 1$ and $z \neq 0$: $$\log(z) = -\displaystyle\sum_{k=1}^{\infty} \dfrac{(-1)^k(z-1)^k}{k},$$ where $\log(z)$ denotes the logarithm.

Proof

References