View source for Li 2(1)=pi^2/6

==Theorem==
The following formula holds:
$$\mathrm{Li}_2(1) = \dfrac{\pi^2}{6},$$
where $\mathrm{Li}$ denotes the [[dilogarithm]] and $\pi$ denotes [[pi]].

==References==
{{BookReference|Polylogarithms and Associated Functions|1926|ed=2nd|edpage=Second Edition|Leonard Lewin|prev=Relationship between Li 2(1),Li 2(-1), and pi|next=}}: (1.9)