View source for 0F0(;;z)=exp(z)

← 0F0(;;z)=exp(z)

Jump to: navigation, search

You do not have permission to edit this page, for the following reason:

The action you have requested is limited to users in the group: Users.

You can view and copy the source of this page.

==Theorem==
The following formula holds:
$$e^z={}_0F_0(;;z),$$
where ${}_0F_0$ denotes the [[hypergeometric pFq]] and $e^z$ denotes the [[exponential]].

==Proof==

==References==

[[Category:Theorem]]

Return to 0F0(;;z)=exp(z).

Retrieved from "http://specialfunctionswiki.org/index.php/0F0(;;z)%3Dexp(z)"