View source for N^2=T(n)+T(n-1)

==Theorem==
The following formula holds for $n=1,2,3,\ldots$:
$$n^2=T(n)+T(n-1),$$
where $T(n)$ denotes the $n$th [[triangular numbers|triangular number]].

==Proof==

==References==
* {{PaperReference|Triangular numbers|1974|V.E. Hoggatt, Jr|author2=Marjorie Bicknell|prev=T(n+1)=T(n)+n+1|next=T(n)^2=T(T(n))+T(T(n)-1)}}

[[Category:Theorem]]
[[Category:Unproven]]