View source for Log a(b)=1/log b(a)

==Theorem==
The following formula holds:
$$\log_a(b) = \dfrac{1}{\log_b(a)},$$
where $\log_a$ denotes [[logarithm base a]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Log base a in terms of logarithm base b|next=log e(z)=log(z)}}: $4.1.20$

[[Category:Theorem]]
[[Category:Unproven]]