View source for Li 2(z)+Li 2(1-z)=pi^2/6-log(z)log(1-z)

==Theorem==
The following formula holds:
$$\mathrm{Li}_2(z)+\mathrm{Li}_2(1-z)=\dfrac{\pi^2}{6} - \log(z)\log(1-z),$$
where $\mathrm{Li}_2$ denotes the [[dilogarithm]], $\pi$ denotes [[pi]], and $log$ denotes the [[logarithm]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Dilogarithm|next=findme}}: $27.7.3$ (<i>note: the letter $f$ denotes the dilogarithm in this formula</i>)<br />

[[Category:Theorem]]
[[Category:Unproven]]