View source for D/dz(z^(nu)H (nu))=z^(nu)H (nu-1)

==Theorem==
The following formula holds:
$$\dfrac{\mathrm{d}}{\mathrm{d}z} \left[ z^{\nu}\mathbf{H}_{\nu}(z) \right]=z^{\nu}\mathbf{H}_{\nu-1}(z),$$
where $\mathbf{H}$ denotes a [[Struve function]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Derivative of Struve H0|next=D/dz(z^(-nu)H (nu))=1/(sqrt(pi)2^(nu)Gamma(nu+3/2))-z^(-nu)H (nu+1)}}: $12.1.12$

[[Category:Theorem]]
[[Category:Unproven]]