View source for H (1/2)(z)=sqrt(2/(pi z))(1-cos(z))

==Theorem==
The following formula holds:
$$\mathbf{H}_{\frac{1}{2}}(z) = \sqrt{\dfrac{2}{\pi z}}(1-\cos(z)),$$
where $\mathbf{H}_{\frac{1}{2}}$ denotes a [[Struve function]], $\pi$ denotes [[pi]], and $\cos$ denotes [[cosine]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=H (-(n+1/2))(z)=(-1)^n J (n+1/2)(z) for integer n geq 0|next=H_(3/2)(z)=sqrt(z/(2pi))(1+2/z^2)-sqrt(2/(pi z))(sin(z)+cos(z)/z)}}: $12.1.16$

[[Category:Theorem]]
[[Category:Unproven]]