View source for Log base a in terms of logarithm base b

==Theorem==
The following formula holds:
$$\log_a(z)=\dfrac{\log_b(z)}{\log_b(a)},$$
where $\log_a$ denotes [[logarithm base a]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Logarithm base a|next=log a(z)=1/log b(a)}}: $4.1.19$

[[Category:Theorem]]
[[Category:Unproven]]