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==Theorem==
The following formula holds:
$$nC_n^{\lambda}(x) = 2\lambda(xC_{n-1}^{\lambda+1}(x) - C_{n-2}^{\lambda+1}(x)),$$
where $C_n^{\lambda}$ denotes [[Gegenbauer C]].

==Proof==

==References==

[[Category:Theorem]]
[[Category:Unproven]]

Return to NC n^(lambda)(x)=2lambda(xC (n-1)^(lambda+1)(x)-C (n-2)^(lambda+1)(x)).

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