View source for Relationship between Li 2(1),Li 2(-1), and pi

==Theorem==
The following formula holds:
$$2\mathrm{Li}_2(1) = 2\mathrm{Li}_2(-1) + \dfrac{\pi^2}{2},$$
where $\mathrm{Li}_2$ denotes the [[dilogarithm]] and $\pi$ denotes [[pi]].

==Proof==

==References==
{{BookReference|Polylogarithms and Associated Functions|1981|ed=2nd|edpage=Second Edition|Leonard Lewin|prev=Relationship between Li 2(-1/x),Li 2(-x),Li 2(-1), and log^2(x)|next=Li_2(1)=pi^2/6}}: $(1.8)$

[[Category:Theorem]]
[[Category:Unproven]]