View source for Series for log(z) for Re(z) greater than 0

==Theorem==
The following formula holds for $\mathrm{Re}(z) \geq 0, z \neq 0$:
$$\log(z) = 2 \displaystyle\sum_{k=1}^{\infty} \left( \dfrac{z-1}{z+1} \right)^k \dfrac{1}{k},$$
where $\log$ denotes the [[logarithm]].
==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Series for log(z) for absolute value of (z-1) less than 1|next=Laurent series for log((z+1)/(z-1)) for absolute value of z greater than 1}}: $4.1.27$

[[Category:Theorem]]
[[Category:Unproven]]