View source for Series for log(z) for Re(z) greater than 1/2

==Theorem==
The following formula holds for $\mathrm{Re}(z) \geq \dfrac{1}{2}$:
$$\log(z) = -\displaystyle\sum_{k=1}^{\infty} \left(\dfrac{z-1}{z} \right)^k \dfrac{1}{k},$$
where $\log$ denotes the [[logarithm]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Taylor series of log(1+z)|next=Series for log(z) for absolute value of (z-1) less than 1}}: $4.1.25$

[[Category:Theorem]]
[[Category:Unproven]]