View source for T(n+1)^2-T(n)^2=(n+1)^3

==Theorem==
The following formula holds for $n=1,2,3,\ldots$:
$$T(n+1)^2-T(n)^2=(n+1)^3,$$
where $T(n)$ denotes the $n$th [[triangular numbers|triangular number]].

==Proof==

==References==
* {{PaperReference|Triangular numbers|1974|V.E. Hoggatt, Jr|author2=Marjorie Bicknell|prev=T(n)^2=T(T(n))+T(T(n)-1)|next=findme}} $(1.5)$

[[Category:Theorem]]
[[Category:Unproven]]