View source for Taylor series of log(1+z)

==Theorem==
The following formula holds for $|z| \leq 1$ and $z \neq -1$:
$$\log(1+z)=-\displaystyle\sum_{k=1}^{\infty} \dfrac{(-1)^kz^k}{k},$$
where $\log$ denotes the [[logarithm]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Relationship between logarithm and logarithm base 10|next=Series for log(z) for Re(z) greater than 1/2}}: 4.1.24

[[Category:Theorem]]
[[Category:Unproven]]