Difference between revisions of "Relationship between logarithmic integral and exponential integral"

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<strong>[[Relationship between logarithmic integral and exponential integral|Theorem]]:</strong> The following formula holds:
 
<strong>[[Relationship between logarithmic integral and exponential integral|Theorem]]:</strong> The following formula holds:
 
$$\mathrm{li}(x)=\mathrm{Ei}( \log(x)),$$
 
$$\mathrm{li}(x)=\mathrm{Ei}( \log(x)),$$
where $\mathrm{li}$ denotes the [[logarithmic integral]] and $\mathrm{Ei}$ denotes the [[exponential integral]].
+
where $\mathrm{li}$ denotes the [[logarithmic integral]] and $\mathrm{Ei}$ denotes the [[exponential integral Ei]].
 
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<div class="mw-collapsible-content">
 
<strong>Proof:</strong> █  
 
<strong>Proof:</strong> █  
 
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</div>
 
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Revision as of 22:08, 16 August 2015

Theorem: The following formula holds: $$\mathrm{li}(x)=\mathrm{Ei}( \log(x)),$$ where $\mathrm{li}$ denotes the logarithmic integral and $\mathrm{Ei}$ denotes the exponential integral Ei.

Proof: