Difference between revisions of "Gamma(1)=1"

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(Created page with "<div class="toccolours mw-collapsible mw-collapsed" style="width:800px"> <strong>Theorem:</strong> The following formula holds: $$\Gamma(1)=1,$$ where $\...")
 
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<strong>Proof:</strong> Compute
 
<strong>Proof:</strong> Compute
 
$$\begin{array}{ll}
 
$$\begin{array}{ll}
\Gamma(1) &= \displaystyle\int_0^{\infty} \xi^{1-1} e^{-\xi} d\xi \\
+
\Gamma(1) &= \displaystyle\int_0^{\infty} \xi^{0} e^{-\xi} d\xi \\
 
&= \displaystyle\int_0^{\infty} e^{-\xi} d\xi \\
 
&= \displaystyle\int_0^{\infty} e^{-\xi} d\xi \\
 
&= \left[ -e^{-\xi} \right]_{0}^{\infty} \\
 
&= \left[ -e^{-\xi} \right]_{0}^{\infty} \\

Revision as of 05:40, 16 May 2016

Theorem: The following formula holds: $$\Gamma(1)=1,$$ where $\Gamma$ denotes the gamma function.

Proof: Compute $$\begin{array}{ll} \Gamma(1) &= \displaystyle\int_0^{\infty} \xi^{0} e^{-\xi} d\xi \\ &= \displaystyle\int_0^{\infty} e^{-\xi} d\xi \\ &= \left[ -e^{-\xi} \right]_{0}^{\infty} \\ &= 1. \end{array}$$ as was to be shown. █