Difference between revisions of "Boole polynomials"

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(Created page with "The Boole polynomials $s_n(x)$ are given by $$\dfrac{(1+t)^x}{1+(1+t)\lambda}=\displaystyle\sum_{k=0}^{\infty} s_n(x) \dfrac{t^k}{k!}.$$")
 
 
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The Boole polynomials $s_n(x)$ are given by
 
The Boole polynomials $s_n(x)$ are given by
 
$$\dfrac{(1+t)^x}{1+(1+t)\lambda}=\displaystyle\sum_{k=0}^{\infty} s_n(x) \dfrac{t^k}{k!}.$$
 
$$\dfrac{(1+t)^x}{1+(1+t)\lambda}=\displaystyle\sum_{k=0}^{\infty} s_n(x) \dfrac{t^k}{k!}.$$
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[[Category:SpecialFunction]]

Latest revision as of 18:42, 24 May 2016

The Boole polynomials $s_n(x)$ are given by $$\dfrac{(1+t)^x}{1+(1+t)\lambda}=\displaystyle\sum_{k=0}^{\infty} s_n(x) \dfrac{t^k}{k!}.$$