Difference between revisions of "Gamma(z)Gamma(1-z)=pi/sin(pi z)"

Revision as of 00:32, 4 June 2016

Theorem: The following relationship between $\Gamma$ and the $\sin$ function holds: $$\Gamma(x)\Gamma(1-x) = \dfrac{\pi}{\sin(\pi x)}.$$

Proof: █

Revision as of 04:16, 20 March 2015 (view source) Tom (talk \| contribs) ← Older edit	Revision as of 00:32, 4 June 2016 (view source) Tom (talk \| contribs) m (Tom moved page Gamma-Sine Relation to Euler's reflection formula for gamma) Newer edit →
(No difference)