Difference between revisions of "Relationship between coth and cot"
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(Created page with "<div class="toccolours mw-collapsible mw-collapsed"> <strong>Theorem:</strong> The following formula holds: $$\coth(z)=i\cot(iz),$$ where...") |
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| − | + | ==Theorem== | |
| − | + | The following formula holds: | |
$$\coth(z)=i\cot(iz),$$ | $$\coth(z)=i\cot(iz),$$ | ||
where $\coth$ denotes the [[coth|hyperbolic cotangent]] and $\cot$ denotes the [[cotangent]]. | where $\coth$ denotes the [[coth|hyperbolic cotangent]] and $\cot$ denotes the [[cotangent]]. | ||
| − | + | ||
| − | + | ==Proof== | |
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| − | + | ==References== | |
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| + | [[Category:Theorem]] | ||
| + | [[Category:Unproven]] | ||
Revision as of 07:48, 8 June 2016
Theorem
The following formula holds: $$\coth(z)=i\cot(iz),$$ where $\coth$ denotes the hyperbolic cotangent and $\cot$ denotes the cotangent.
