Difference between revisions of "Derivative of sinh"
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− | + | ==Theorem== | |
− | + | The following formula holds: | |
− | + | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \sinh(z) = \cosh(z),$$ | |
− | + | where $\sinh$ denotes the [[sinh|hyperbolic sine]] and $\cosh$ denotes the [[cosh|hyperbolic cosine]]. | |
− | + | ||
− | + | ==Proof== | |
+ | From the definition, | ||
+ | $$\sinh(z) = \dfrac{e^z-e^{-z}}{2},$$ | ||
+ | and so using the [[derivative of the exponential function]], the [[derivative is a linear operator|linear property of the derivative]], the [[chain rule]], and the definition of the hyperbolic cosine, | ||
+ | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \sinh(z)=\dfrac{e^z + e^{-z}}{2}=\cosh(z),$$ | ||
+ | as was to be shown. █ | ||
+ | |||
+ | ==References== | ||
+ | |||
+ | [[Category:Theorem]] | ||
+ | [[Category:Proven]] |
Latest revision as of 07:52, 8 June 2016
Theorem
The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \sinh(z) = \cosh(z),$$ where $\sinh$ denotes the hyperbolic sine and $\cosh$ denotes the hyperbolic cosine.
Proof
From the definition, $$\sinh(z) = \dfrac{e^z-e^{-z}}{2},$$ and so using the derivative of the exponential function, the linear property of the derivative, the chain rule, and the definition of the hyperbolic cosine, $$\dfrac{\mathrm{d}}{\mathrm{d}z} \sinh(z)=\dfrac{e^z + e^{-z}}{2}=\cosh(z),$$ as was to be shown. █