Difference between revisions of "Euler product for Riemann zeta"

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==Theorem==
 
==Theorem==
 
The following formula holds for $\mathrm{Re}(z)>1$:
 
The following formula holds for $\mathrm{Re}(z)>1$:
$$\zeta(z)=\displaystyle\sum_{n=1}^{\infty} \dfrac{1}{n^z} = \displaystyle\prod_{p \mathrm{\hspace{2pt} prime}} \dfrac{1}{1-p^{-z}},$$
+
$$\zeta(z)=\displaystyle\prod_{p \mathrm{\hspace{2pt} prime}} \dfrac{1}{1-p^{-z}},$$
 
where $\zeta$ is the [[Riemann zeta function]].
 
where $\zeta$ is the [[Riemann zeta function]].
  

Revision as of 19:46, 9 June 2016

Theorem

The following formula holds for $\mathrm{Re}(z)>1$: $$\zeta(z)=\displaystyle\prod_{p \mathrm{\hspace{2pt} prime}} \dfrac{1}{1-p^{-z}},$$ where $\zeta$ is the Riemann zeta function.

Proof

References