Difference between revisions of "Derivative of cosh"
From specialfunctionswiki
(Created page with "<div class="toccolours mw-collapsible mw-collapsed" style="width:800px"> <strong>Proposition:</strong> $\dfrac{d}{dx}$$\cosh$$(x)=$Sinh|$\sin...") |
|||
(4 intermediate revisions by the same user not shown) | |||
Line 1: | Line 1: | ||
− | + | ==Theorem== | |
− | + | The following formula holds: | |
− | + | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \cosh(z) = \sinh(z),$$ | |
− | + | where $\cosh$ denotes the [[Cosh|hyperbolic cosine]] and $\sinh$ denotes the [[sinh|hyperbolic sine]]. | |
− | + | ||
− | + | ==Proof== | |
+ | From the definition, | ||
+ | $$\mathrm{cosh}(z)=\dfrac{e^z + e^{-z}}{2}$$ | ||
+ | and so using the [[derivative of the exponential function]], the [[derivative is a linear operator|linear property of the derivative]], the [[chain rule]], and the definition of the hyperbolic sine, | ||
+ | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \cosh(z)=\dfrac{e^z - e^{-z}}{2}=\sinh(z),$$ | ||
+ | as was to be shown. █ | ||
+ | |||
+ | ==References== | ||
+ | |||
+ | [[Category:Theorem]] | ||
+ | [[Category:Proven]] |
Latest revision as of 23:59, 16 June 2016
Theorem
The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \cosh(z) = \sinh(z),$$ where $\cosh$ denotes the hyperbolic cosine and $\sinh$ denotes the hyperbolic sine.
Proof
From the definition, $$\mathrm{cosh}(z)=\dfrac{e^z + e^{-z}}{2}$$ and so using the derivative of the exponential function, the linear property of the derivative, the chain rule, and the definition of the hyperbolic sine, $$\dfrac{\mathrm{d}}{\mathrm{d}z} \cosh(z)=\dfrac{e^z - e^{-z}}{2}=\sinh(z),$$ as was to be shown. █