Difference between revisions of "Relationship between Bessel I sub 1/2 and sinh"

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==Theorem==
<strong>[[Relationship between Bessel I sub 1/2 and sinh|Theorem]]:</strong> The following formula holds:
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The following formula holds:
$$I_{\frac{1}{2}}(z)=\sqrt{\dfrac{2}{\pi z}}\sinh(z).$$
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$$I_{\frac{1}{2}}(z)=\sqrt{\dfrac{2}{\pi z}}\sinh(z),$$
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where $I_{\frac{1}{2}}$ denotes the [[Modified Bessel I sub nu|modified Bessel function of the first kind]] and $\sinh$ denotes the [[Sinh|hyperbolic sine]].
<strong>Proof:</strong> █
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==Proof==
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==References==
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 07:54, 8 June 2016

Theorem

The following formula holds: $$I_{\frac{1}{2}}(z)=\sqrt{\dfrac{2}{\pi z}}\sinh(z),$$ where $I_{\frac{1}{2}}$ denotes the modified Bessel function of the first kind and $\sinh$ denotes the hyperbolic sine.

Proof

References