Difference between revisions of "Relationship between cosh and cos"

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==Theorem==
<strong>[[Relationship between cosh and cos|Theorem]]:</strong> The following formula holds:
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The following formula holds:
 
$$\cosh(z)=\cos(iz),$$
 
$$\cosh(z)=\cos(iz),$$
 
where $\cosh$ is the [[cosh|hyperbolic cosine]] and $\cos$ is the [[cosine]].
 
where $\cosh$ is the [[cosh|hyperbolic cosine]] and $\cos$ is the [[cosine]].
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<strong>Proof:</strong> █
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==Proof==
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==References==
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Relationship between sinh and sin|next=Relationship between tanh and tan}}: $4.5.8$
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 19:38, 22 November 2016

Theorem

The following formula holds: $$\cosh(z)=\cos(iz),$$ where $\cosh$ is the hyperbolic cosine and $\cos$ is the cosine.

Proof

References