Difference between revisions of "Integral of inverse erf from 0 to 1"

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==Theorem==
 
==Theorem==
 
The following formula holds:
 
The following formula holds:
$$\displaystyle\int_0^1 \mathrm{erf}^{-1}(x) \mathrm{d}x=\dfrac{1}{\sqrt{\pi}}.$$
+
$$\displaystyle\int_0^1 \mathrm{erf}^{-1}(x) \mathrm{d}x=\dfrac{1}{\sqrt{\pi}},$$
 +
where $\mathrm{erf}^{-1}$ denotes the [[inverse error function]] and $\pi$ denotes [[pi]].
  
 
==Proof==
 
==Proof==

Latest revision as of 04:46, 16 September 2016

Theorem

The following formula holds: $$\displaystyle\int_0^1 \mathrm{erf}^{-1}(x) \mathrm{d}x=\dfrac{1}{\sqrt{\pi}},$$ where $\mathrm{erf}^{-1}$ denotes the inverse error function and $\pi$ denotes pi.

Proof

References