Difference between revisions of "Beta in terms of gamma"

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<strong>[[Beta in terms of gamma|Theorem]]:</strong> The following formula holds:  
 
<strong>[[Beta in terms of gamma|Theorem]]:</strong> The following formula holds:  
 
$$B(x,y)=\dfrac{\Gamma(x)\Gamma(y)}{\Gamma(x+y)},$$
 
$$B(x,y)=\dfrac{\Gamma(x)\Gamma(y)}{\Gamma(x+y)},$$
where $B$ denotes the [[beta]] and $\Gamma$ denotes the [[gamma function]].  
+
where $B$ denotes the [[beta]] function and $\Gamma$ denotes the [[gamma]] function.  
 
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<div class="mw-collapsible-content">
 
<strong>Proof:</strong> █  
 
<strong>Proof:</strong> █  
 
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</div>
 
</div>
 
</div>

Revision as of 00:48, 21 March 2015

Theorem: The following formula holds: $$B(x,y)=\dfrac{\Gamma(x)\Gamma(y)}{\Gamma(x+y)},$$ where $B$ denotes the beta function and $\Gamma$ denotes the gamma function.

Proof: