Difference between revisions of "Legendre P"
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<strong>Theorem:</strong> The following formula holds: | <strong>Theorem:</strong> The following formula holds: | ||
− | $$\dfrac{1}{\sqrt{1-2xt+t^2}} = \displaystyle\sum_{k=0}^{\infty} | + | $$\dfrac{1}{\sqrt{1-2xt+t^2}} = \displaystyle\sum_{k=0}^{\infty} P_k(x)t^k.$$ |
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<strong>Proof:</strong> █ | <strong>Proof:</strong> █ |
Revision as of 23:59, 19 May 2015
The Legendre polynomials are orthogonal polynomials defined by the formula $$P_n(x) = \dfrac{1}{2^n} \displaystyle\sum_{k=0}^n {n \choose k}^2 (x-1)^{n-k}(x+1)^k.$$
$$\begin{array}{ll} P_0(x) &= 1 \\ P_1(x) &= x \\ P_2(x) &= \dfrac{1}{2}(3x^2-1) \\ P_3(x) &= \dfrac{1}{2}(5x^3-3x) \\ P_4(x) &= \dfrac{1}{8}(35x^4-30x^2+3) \\ P_5(x) &= \dfrac{1}{8}(63x^5-70x^3+15x) \\ \vdots \end{array}$$
Properties
Theorem: The Legendre polynomials satisfy the differential equation $$(1-x^2)P_k(x)-2xP_k'(x)+k(k+1)P_k(x)=0.$$
Proof: █
Theorem: The following formula holds: $$\dfrac{1}{\sqrt{1-2xt+t^2}} = \displaystyle\sum_{k=0}^{\infty} P_k(x)t^k.$$
Proof: █
Theorem: (Rodrigues' formula) The following formula holds: $$P_n(x)=\dfrac{1}{2^nn!}\dfrac{d^n}{dx^n} [(x^2-1)^n].$$
Proof: █
Theorem: (Orthogonality) The following formula holds: $$\displaystyle\int_{-1}^1 P_m(x)P_n(x)dx = \dfrac{2}{2n+1} \delta_{mn},$$ where $P_n$ denotes Legendre polynomials and $\delta$ denotes the Dirac delta.
Proof: █