Difference between revisions of "Derivative of cosh"

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(Created page with "<div class="toccolours mw-collapsible mw-collapsed" style="width:800px"> <strong>Proposition:</strong> $\dfrac{d}{dx}$$\cosh$$(x)=$Sinh|$\sin...")
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Revision as of 05:32, 20 March 2015

Proposition: $\dfrac{d}{dx}$$\cosh$$(x)=$$\sinh$$(x)$

Proof: