Difference between revisions of "Relationship between cosh and hypergeometric 0F1"
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Revision as of 05:15, 19 August 2015
Theorem: The following formula holds: $$\cosh(az)=az {}_0F_1 \left( ; \dfrac{1}{2}; \dfrac{(az)^2}{4} \right),$$ where $\cosh$ denotes the hyperbolic cosine and ${}_0F_1$ denotes the hypergeometric pFq.
Proof: █