Difference between revisions of "Relationship between coth and cot"
From specialfunctionswiki
(Created page with "<div class="toccolours mw-collapsible mw-collapsed"> <strong>Theorem:</strong> The following formula holds: $$\coth(z)=i\cot(iz),$$ where...") |
(No difference)
|
Revision as of 18:56, 25 August 2015
Theorem: The following formula holds: $$\coth(z)=i\cot(iz),$$ where $\coth$ denotes the hyperbolic cotangent and $\cot$ denotes the cotangent.
Proof: █