Difference between revisions of "Arcsin"
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[https://www.youtube.com/watch?v=JZ9Ku1TTeA4 What is arcsin(x)?]<br /> | [https://www.youtube.com/watch?v=JZ9Ku1TTeA4 What is arcsin(x)?]<br /> | ||
[https://www.youtube.com/watch?v=4CY7RIUhs2s What is the inverse of arcsin(ln(x))?]<br /> | [https://www.youtube.com/watch?v=4CY7RIUhs2s What is the inverse of arcsin(ln(x))?]<br /> | ||
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| + | =See Also= | ||
| + | [[Sine]] <br /> | ||
| + | [[Sinh]] <br /> | ||
| + | [[Arcsinh]] | ||
=References= | =References= | ||
Revision as of 18:35, 11 November 2015
The function $\mathrm{arcsin} \colon [-1,1] \rightarrow \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right]$ is the inverse function of the sine function.
- Arcsin.png
Graph of $\mathrm{arcsin}$ on $[-1,1]$.
- Complex arcsin.jpg
Domain coloring of analytic continuation $\mathrm{arcsin}$.
Contents
Properties
Proposition: $\dfrac{d}{dz} \mathrm{arcsin(z)} = \dfrac{1}{\sqrt{1-z^2}}$
Proof: If $\theta=\mathrm{arcsin}(z)$ then $\sin(\theta)=z$. Now use implicit differentiation with respect to $z$ to get $$\cos(\theta)\theta'=1.$$ The following image shows that $\cos(\mathrm{arcsin}(z))=\sqrt{1-z^2}$:
).png)
Hence substituting back in $\theta=\mathrm{arccos}(z)$ yields the formula $$\dfrac{d}{dz} \mathrm{arcsin(z)} = \dfrac{1}{\cos(\mathrm{arcsin(z)})} = \dfrac{1}{\sqrt{1-z^2}}. █$$
Proposition: $\displaystyle\int \mathrm{arcsin}(z) dz = \sqrt{1-z^2}+z\mathrm{arcsin}(z)+C$
Proof: █
Proposition: $\mathrm{arcsin}(z) = \mathrm{arccsc}\left( \dfrac{1}{z} \right)$
Proof: █
Proposition: $\mathrm{arcsin}(z)=\displaystyle\sum_{k=0}^{\infty} \dfrac{\left(\frac{1}{2} \right)_n}{(2n+1)n!}x^{2n+1}$
Proof: █
Relationship between arcsin and hypergeometric 2F1
Videos
Inverse Trig Functions: Arcsin
Integrate x*arcsin(x)
What is arcsin(x)?
What is the inverse of arcsin(ln(x))?
