Difference between revisions of "Derivative of arcsinh"
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<strong>[[Derivative of arcsinh|Theorem]]:</strong> The following formula holds: | <strong>[[Derivative of arcsinh|Theorem]]:</strong> The following formula holds: | ||
| − | $$\dfrac{d}{ | + | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \mathrm{arcsinh}(z) = \dfrac{1}{\sqrt{1+z^2}},$$ |
| + | where $\mathrm{arcsinh}$ denotes the [[arcsinh|inverse hyperbolic sine]]. | ||
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<strong>Proof:</strong> █ | <strong>Proof:</strong> █ | ||
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Revision as of 19:16, 15 May 2016
Theorem: The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \mathrm{arcsinh}(z) = \dfrac{1}{\sqrt{1+z^2}},$$ where $\mathrm{arcsinh}$ denotes the inverse hyperbolic sine.
Proof: █
