Difference between revisions of "Derivative of tanh"
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| − | <strong>[[Derivative of tanh|Proposition]]:</strong> $\dfrac{d}{ | + | <strong>[[Derivative of tanh|Proposition]]:</strong> The following formula holds: |
| + | $$\dfrac{\mathrm{d}}{\mathrm{d}x} \tanh(x)=\sech(x),$$ | ||
| + | where $\tanh$ denotes the [[tanh|hyperbolic tangent]] and $\sech$ denotes the [[sech|hyperbolic secant]]. | ||
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<strong>Proof:</strong> █ | <strong>Proof:</strong> █ | ||
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Revision as of 20:28, 15 May 2016
Proposition: The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}x} \tanh(x)=\sech(x),$$ where $\tanh$ denotes the hyperbolic tangent and $\sech$ denotes the hyperbolic secant.
Proof: █
