Difference between revisions of "Derivative of tanh"
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<strong>[[Derivative of tanh|Proposition]]:</strong> The following formula holds: | <strong>[[Derivative of tanh|Proposition]]:</strong> The following formula holds: | ||
| − | $$\dfrac{\mathrm{d}}{\mathrm{d}x} \tanh(x)=\sech(x),$$ | + | $$\dfrac{\mathrm{d}}{\mathrm{d}x} \tanh(x)=\mathrm{sech}(x),$$ |
| − | where $\tanh$ denotes the [[tanh|hyperbolic tangent]] and $\sech$ denotes the [[sech|hyperbolic secant]]. | + | where $\tanh$ denotes the [[tanh|hyperbolic tangent]] and $\mathrm{sech}$ denotes the [[sech|hyperbolic secant]]. |
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<strong>Proof:</strong> █ | <strong>Proof:</strong> █ | ||
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Revision as of 20:28, 15 May 2016
Proposition: The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}x} \tanh(x)=\mathrm{sech}(x),$$ where $\tanh$ denotes the hyperbolic tangent and $\mathrm{sech}$ denotes the hyperbolic secant.
Proof: █
