Difference between revisions of "Antiderivative of arcsin"

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(Created page with "<div class="toccolours mw-collapsible mw-collapsed"> <strong>Theorem:</strong> The following formula holds: $$\displaystyle\int \mathrm{arcsin}(z)...")
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Revision as of 03:38, 16 May 2016

Theorem: The following formula holds: $$\displaystyle\int \mathrm{arcsin}(z) \mathrm{d}z = \sqrt{1-z^2}+z\mathrm{arcsin}(z)+C,$$ where $\mathrm{arcsin}$ denotes the inverse sine function.

Proof: