Difference between revisions of "Taylor series of log(1-z)"

From specialfunctionswiki
Jump to: navigation, search
(Created page with "==Theorem== The following formula holds: $$\log(1-z)=-\displaystyle\sum_{k=1}^{\infty} \dfrac{z^k}{k},$$ where $\log$ denotes the logarithm. ==Proof== =References= {{Boo...")
(No difference)

Revision as of 23:41, 3 June 2016

Theorem

The following formula holds: $$\log(1-z)=-\displaystyle\sum_{k=1}^{\infty} \dfrac{z^k}{k},$$ where $\log$ denotes the logarithm.

Proof

References

1926: Leonard Lewin: Polylogarithms and Associated Functions (2nd ed.) ... (previous): (1.2)