Difference between revisions of "Li 2(1)=pi^2/6"
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Revision as of 00:02, 4 June 2016
Theorem
The following formula holds: $$\mathrm{Li}_2(1) = \dfrac{\pi^2}{6},$$ where $\mathrm{Li}$ denotes the dilogarithm and $\pi$ denotes pi.
References
1926: Leonard Lewin: Polylogarithms and Associated Functions (2nd ed.) ... (previous): (1.9)
