Difference between revisions of "Binomial coefficient (n choose 0) equals 1"
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| − | * {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Binomial coefficient ((n+1) choose k) equals (n choose k) + (n choose (k-1))|next=}: 3.1.5 | + | * {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Binomial coefficient ((n+1) choose k) equals (n choose k) + (n choose (k-1))|next=Binomial coefficient (n choose n) equals 1}}: 3.1.5 |
Revision as of 02:44, 4 June 2016
Theorem
The following formula holds: $${n \choose 0} = 1,$$ where ${n \choose 0}$ denotes the binomial coefficient.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): 3.1.5
