Difference between revisions of "Quotient rule for derivatives"

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Revision as of 03:11, 4 June 2016

Theorem

Let $f$ and $g$ be differentiable functions with $g'(x) \neq 0$ for all $x$. Then the following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}x} \left[ \dfrac{f(x)}{g(x)} \right] = \dfrac{g(x)f'(x)-f(x)g'(x)}{g(x)^2},$$ where $\dfrac{\mathrm{d}}{\mathrm{d}x}$ denotes the derivative operator.

Proof

References