Difference between revisions of "Cotangent"

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=References=
 
=References=
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Tangent|next=Cotangent}}: 4.3.147
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Tangent|next=Versine}}: 4.3.147
  
 
<center>{{:Trigonometric functions footer}}</center>
 
<center>{{:Trigonometric functions footer}}</center>
  
 
[[Category:SpecialFunction]]
 
[[Category:SpecialFunction]]

Revision as of 04:31, 6 June 2016

The cotangent function is defined by the formula $$\cot(z)=\dfrac{1}{\tan z} \equiv \dfrac{\cos(z)}{\sin(z)},$$ where $\tan$ denotes the tangent function.

Properties

Theorem

The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z}\cot(z)=-\csc^2(z),$$ where $\cot$ denotes the cotangent and $\csc$ denotes the cosecant.

Proof

Apply the quotient rule to the definition of cotangent using derivative of sine and derivative of cosine to see $$\begin{array}{ll} \dfrac{\mathrm{d}}{\mathrm{d}z} \cot(z) &= \dfrac{\mathrm{d}}{\mathrm{d}x} \left[ \dfrac{\cos(z)}{\sin(z)} \right] \\ &= \dfrac{-\sin^2(z)-\cos^2(z)}{\sin^2(z)} \\ &= -\dfrac{\sin^2(z)+\cos^2(z)}{\sin^2(z)}. \end{array}$$ Now apply the Pythagorean identity for sin and cos and the definition of cosecant to see $$\dfrac{\mathrm{d}}{\mathrm{d}z} \cot(z) = -\dfrac{1}{\sin^2(z)} = -\csc^2(z),$$ as was to be shown. █

References

Theorem

The following formula holds: $$\cot(z)=i\coth(iz),$$ where $\cot$ denotes the cotangent and $\coth$ denotes the hyperbolic cotangent.

Proof

References

Theorem

The following formula holds: $$\coth(z)=i\cot(iz),$$ where $\coth$ denotes the hyperbolic cotangent and $\cot$ denotes the cotangent.

Proof

References

Theorem

The following formula holds: $$\cot(\mathrm{gd}(x))=\mathrm{csch}(x),$$ where $\cot$ is the cotangent, $\mathrm{gd}$ is the Gudermannian, and $\mathrm{csch}$ is the hyperbolic cosecant.

Proof

References

Theorem

The following formula holds: $$\mathrm{csch}(\mathrm{gd}^{-1}(x))=\cot(x),$$ where $\mathrm{csch}$ is the hyperbolic cosecant, $\mathrm{gd}^{-1}$ is the inverse Gudermannian, and $\cot$ is the cotangent.

Proof

References

See Also

Arccot
Coth
Arccoth

References

<center>Trigonometric functions
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