Difference between revisions of "Relationship between cos and cosh"
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(Created page with "<div class="toccolours mw-collapsible mw-collapsed"> <strong>Theorem:</strong> The following formula holds: $$\cos(z)=\cosh(iz),$$ where...") |
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| − | + | ==Theorem== | |
| − | + | The following formula holds: | |
$$\cos(z)=\cosh(iz),$$ | $$\cos(z)=\cosh(iz),$$ | ||
where $\cos$ is the [[cosine]] and $\cosh$ is the [[cosh|hyperbolic cosine]]. | where $\cos$ is the [[cosine]] and $\cosh$ is the [[cosh|hyperbolic cosine]]. | ||
| − | + | ||
| − | + | ==Proof== | |
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| − | + | ==References== | |
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| + | [[Category:Theorem]] | ||
| + | [[Category:Unproven]] | ||
Revision as of 07:41, 8 June 2016
Theorem
The following formula holds: $$\cos(z)=\cosh(iz),$$ where $\cos$ is the cosine and $\cosh$ is the hyperbolic cosine.
