Difference between revisions of "Recurrence relation of exponential integral E"
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Latest revision as of 00:23, 8 August 2016
Theorem
The following formula holds for $n=1,2,3,\ldots$: $$E_{n+1}(z)=\dfrac{e^{-z}-zE_n(z)}{n},$$ where $E_n$ denotes the exponential integral E.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $5.1.14$